Obtain the roots of the following equation us | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To solve the equation $m^{2} - 18m + 81 = 0$ by the method of completing the square:$1$. The equation is already in the form $m^{2} - 18m = -81$.$

Vedclass · Accepted Answer

$9, 9$

Vedclass · Answer

(B) To solve the equation $m^{2} - 18m + 81 = 0$ by the method of completing the square:$1$. The equation is already in the form $m^{2} - 18m = -81$.$2$. To complete the square,we add the square of half the coefficient of $m$ to both sides. The coefficient of $m$ is $-18$,so half of it is $-9$,and $(-9)^{2} = 81$.$3$. Adding $81$ to both sides: $m^{2} - 18m + 81 = -81 + 81$.$4$. This simplifies to $(m - 9)^{2} = 0$.$5$. Taking the square root of both sides,we get $m - 9 = 0$,which implies $m = 9$.$6$. Since it is a quadratic equation,the roots are $9, 9$.

Obtain the roots of the following equation using the method of 'completing the square': $m^{2} - 18m + 81 = 0$

Similar Questions

State whether the quadratic equation $(x+1)(x-2)+x=0$ has two distinct real roots. Justify your answer.

Which one of the following is not a quadratic equation?

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $\frac{1}{4} x^{2} - 2x + 1 = 0$.

Is $0.2$ a root of the equation $x^{2}-0.4=0$? Justify.

Verify whether the given value of $x = \frac{-2}{m+n}$ is a solution of the quadratic equation $(m+n)^{2} x^{2} + (m+n) x - 2 = 0$ or not.

Vedclass Test Series

Exam Paper Generator

Online Exam Module